Jawab:
1. = Luas sisi alas + ( 4 × sisi tegak)
= (p×l) + ((2/ × p×t/2/ ) + (2/ × l×t/2/))
= (p×l) + (p×t) + (l×t)
= (12 cm × 6 cm) + (12 cm × 10 cm) + (6 cm × 10 cm)
= 72 cm² + 120 cm² + 60 cm²
= 250 cm²
2. = Luas sisi alas + ( 4 × sisi tegak)
= (p×l) + ((2/ × p×t/2/ ) + (2/ × l×t/2/))
= (p×l) + (p×t) + (l×t)
= (12 cm × 6 cm) + (12 cm × 8 cm) + (6 cm × 8 cm)
= 72 cm² + 96 cm² + 48 cm²
= 216 cm²
3. =Luas sisi alas + ( 4 × sisi tegak)
= (p×l) + ((2/ × p×t/2/ ) + (2/ × l×t/2/))
= (p×l) + (p×t) + (l×t)
= (7 cm × 7 cm) + (7 cm × 15 cm) + (7 cm × 15 cm)
= 49 cm² + 105 cm² + 105 cm²
= 259 cm²
4. = Luas sisi alas + ( 4 × sisi tegak)
= (p×l) + ((2/ × p×t/2/ ) + (2/ × l×t/2/))
= (p×l) + (p×t) + (l×t)
= (16 cm × 9 cm) + (16 cm × 13 cm) + (9 cm × 13 cm)
= 144 cm² + 208 cm² + 117 cm²
= 469 cm²
Penjelasan:
2/ itu maskudnya 2 nya di coret ya..
p×t/2/ itu p kali t per 2.. terus 2 nya di coret yaa
maaf ya kalo jadi bingung..
Semoga membantu ^^
